1.

If a =9+2√6 and b =57/a,then what will be the value of a^2+b^2

Answer»

A^2=(9+2¦6)^2
=81+2×9×2¦6+4×6
=81+36¦6+24
=105¦6

b^2=(57/a)^2
=3249/105¦6
=1083/35¦6

a^2+b^2=105¦6+1083/35¦6
=(3675×6+1083)/35¦6
=(22050+1083)/35¦6
=23133/35¦6


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