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If A=(6i-8j) units, B=(8i-3j) units, and C=(26i-19j), determine a and b such that aA+bB+cC=0 .....plz show the working clearly...drop a picture if u can...

Answer»

f a , b so that aA + BB + C = 0 is a = -1.613 and b = 2.04That is SINCE c is not given I am assuming it to be 1.aA + bB = - Ca(6i - 8j) + b(8i -3j) = -26i + 19jequating all is and js,6a + 8b = -26 ==> (3a + 4B = -13)x8 = 24a + 32b = -104---(1)-8a + -3b = 19==> (8a + 3b = -19)x 3 = 24a + 9b = -57---(2) equation (1) - (2) ==>23b = -47===> b = -47/23 = - 2.04from (1)a = (-13 - 4b)/3 = (-13 + 4x47/23)/3 = (-598 + 604)/(23x3) = -1.613



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