1.

If à = 3i– 2j+ 4k B = 3i – 2j + 4k C = i + 2j + 2k then find the value ofẢx (B x C)​

Answer»

tion:A×(B×C)1) B×CB:- 3i - 2j + 4kC:- i + 2j + 2k By APPLYING determinant methodB×C= (-4-8)i-(6-4)j+(6+2)K = -12i - 2j + 8k2) AX(B×C)A:- 3i - 2j + 4k(B×C):- -12i - 2j + 8k = (-16+8)i-(24+48)j+(-6-24)k=》-8i - 72j - 30k



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