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If a=3 and t6=27,find the sum of the first sixth term of the Ap |
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Answer» Answer: S6 = 90 Step-by-step explanation: hello friend given a = 3 which means FIRST term and t6 = 27 which means sixth term generally tn = a + (n-1)d given t6 = 27 substitute t = 6 in tn = a + (n-1)d which means t6 = a + 5D a + 5d = 27 3 + 5d = 27 5d = 24 d = 24/5 where d is common difference in ap to first sum of first six terms sum of n terms of an ap is Sn = n/2[2a+(n-1)d] we have to find S6 S6 = 6/2 [ 2(3)+(6-1)24/5] = 3[ 6 + 5 × 24/5] = 3[ 6 + 24] = 3(30) = 90 hope it helps you MARK me brainliest if you like my explanation and answer |
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