If a^2+b^2=2ab then log(a-b)^2

1.	If a^2+b^2=2ab then log(a-b)^2
Answer» Step-by-step EXPLANATION: $a ^{2} + b ^{2} = 2ab \\ a ^{2} + b ^{2} - 2ab = 0 \\ (a - b) ^{2} = 0 \\ find \: \: \: \log(a - b) ^{2} \\ \\ log0 \: \: \: \: \: \: log0 = 1 \\ = 1$ HOPE it will HELP you THANKS FOLLOW me

Answer»

Step-by-step EXPLANATION:

$a ^{2} + b ^{2} = 2ab \\ a ^{2} + b ^{2} - 2ab = 0 \\ (a - b) ^{2} = 0 \\ find \: \: \: \log(a - b) ^{2} \\ \\ log0 \: \: \: \: \: \: log0 = 1 \\ = 1$

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If a^2+b^2=2ab then log(a-b)^2​

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If a^2+b^2=2ab then log(a-b)^2