If A=[2−3−41], then adj(3A2+12A) is equal to

1.	If A=[2−3−41], then adj(3A2+12A) is equal to
Answer» If $A = [\begin{matrix} 2 & - 3 - 4 & 1 \end{matrix}], then a d j (3 A^{2} + 12 A)$ is equal to

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