if A = [[2, 3] [4, 7]] B = [[1, 3] [- 2, 5]] find 2A+3B-5I where I is

1.	if A = [[2, 3] [4, 7]] B = [[1, 3] [- 2, 5]] find 2A+3B-5I where I is identiy Matrix of order
Answer» \(A = \begin{bmatrix}2 & 3 \\[0.3em]4 & 7 \\[0.3em]\end{bmatrix}\), \(B = \begin{bmatrix}1 & 3 \\[0.3em]-2 &5 \\[0.3em]\end{bmatrix}\), \(I = \begin{bmatrix}1 & 0 \\[0.3em]0 & 1 \\[0.3em]\end{bmatrix}\) Now, 2A + 3B - 5I = \( 2\begin{bmatrix}2 & 3 \\[0.3em]4 & 7 \\[0.3em]\end{bmatrix}\)+ \( 3\begin{bmatrix}1& 3 \\[0.3em]-2 & 5 \\[0.3em]\end{bmatrix}\) - \( 5\begin{bmatrix}1& 0 \\[0.3em]0 & 1 \\[0.3em]\end{bmatrix}\) = \( \begin{bmatrix}4+3-5 & 6+9 \\[0.3em]8-6 & 14+15-5 \\[0.3em]\end{bmatrix}\) = \( \begin{bmatrix}2 & 15 \\[0.3em]2 &24 \\[0.3em]\end{bmatrix}\)

if A = [[2, 3] [4, 7]] B = [[1, 3] [- 2, 5]] find 2A+3B-5I where I is identiy Matrix of order

Answer»

\(A = \begin{bmatrix}2 & 3 \\[0.3em]4 & 7 \\[0.3em]\end{bmatrix}\), \(B = \begin{bmatrix}1 & 3 \\[0.3em]-2 &5 \\[0.3em]\end{bmatrix}\), \(I = \begin{bmatrix}1 & 0 \\[0.3em]0 & 1 \\[0.3em]\end{bmatrix}\)

Now,

2A + 3B - 5I = \( 2\begin{bmatrix}2 & 3 \\[0.3em]4 & 7 \\[0.3em]\end{bmatrix}\)+ \( 3\begin{bmatrix}1& 3 \\[0.3em]-2 & 5 \\[0.3em]\end{bmatrix}\) - \( 5\begin{bmatrix}1& 0 \\[0.3em]0 & 1 \\[0.3em]\end{bmatrix}\)

= \( \begin{bmatrix}4+3-5 & 6+9 \\[0.3em]8-6 & 14+15-5 \\[0.3em]\end{bmatrix}\)

= \( \begin{bmatrix}2 & 15 \\[0.3em]2 &24 \\[0.3em]\end{bmatrix}\)

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