If `a_(1)=a, a_(2)=b, a_(n+2)=(a_(n+1)+a_(n))/2, nge 0` then `lim_(n to oo) a_(n)` is `(a+lamda_(1)b)/(lamda_(2)), (lamda_(1),lamda_(2) epsilonI)` where `lamda_(1)+lamda_(2)` is _______

If `a_(1)=a, a_(2)=b, a_(n+2)=(a_(n+1)+a_(n))/2, nge 0` then `lim_(n t

1.	If `a_(1)=a, a_(2)=b, a_(n+2)=(a_(n+1)+a_(n))/2, nge 0` then `lim_(n to oo) a_(n)` is `(a+lamda_(1)b)/(lamda_(2)), (lamda_(1),lamda_(2) epsilonI)` where `lamda_(1)+lamda_(2)` is _______
Answer» Correct Answer - 5 `lim_(nto oo) a_(n)=a+(b-a)/2+(b-a)/8+…=a+2/3(b-a)=(a+2b)/3`

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If `a_(1)=a, a_(2)=b, a_(n+2)=(a_(n+1)+a_(n))/2, nge 0` then `lim_(n to oo) a_(n)` is `(a+lamda_(1)b)/(lamda_(2)), (lamda_(1),lamda_(2) epsilonI)` where `lamda_(1)+lamda_(2)` is _______

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