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If a=1/a-5, find (i)a-1/a (ii)a+1/a (iii)a^2-1/a^2, please, please , please answer it for me. |
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Answer» Answer: a-1/a=-5 (obvious from PROBLEM) a'2+5a-1=0 (MULTIPLY by a to the GIVEN EQN) then a=-5-+ROOT(29) a+1/a =(a'2+1)/a=(2-5a)/a =2/a -5 =2/(-5+root(29)) -5 =2*(-5-root(29))/(-4) -5 2*(5+root(29))/4-5 =10/4+2*root(29)/4 -5 =(root(29))/2 -5/2 |
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