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If `A=[1 2 2 2 1-2a2b]`is a matrix satisfying the equation `AA^T=""9I`,where `I`is `3xx3`identity matrix, then the ordered pair (a,b) is equal to :(1) `(2,-1)`(2) `(-2,""1)`(3) (2, 1) (4) `(-2,-1)`A. (2, 1)B. (-2, -1)C. `(2, -1)`D. `(-2, 1)` |
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Answer» Correct Answer - B `therefore A A^(T) = 9 I` `[[1,2,2],[2,1,-2],[a,2,b]][[1,2,a],[2,1,2],[2,-2,b]]= 9 [[1,0,0],[0,1,0],[0,0,1]]` `rArr [[9,0,a+ 4+ 2b],[0,9,2a+2-2b],[a+4+2b,2a+2-2b,a^(2)+4+b^(2)]]= [[9,0,0],[0,9,0],[0,0,9]]` On comparing, we get `a + 2b + 4 = 0 " " (i)` ` 2a- 2b+2=0" "(ii)` From Eqs. (i) and (ii), we get `a = -2,` `b= -1` `therefore` Prdered pair is `(-2, -1)`. |
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