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If A−1=⎡⎢⎣−1350−2−2002⎤⎥⎦ then the value of 14(det(adj(adj A)))–1 is equal to |
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Answer» If A−1=⎡⎢⎣−1350−2−2002⎤⎥⎦ then the value of 14(det(adj(adj A)))–1 is equal to |
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