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If α=1+12+13+⋯⋯+1101 and β=99∑r=1r(102−r)(101−r), then the value of α+β is |
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Answer» If α=1+12+13+⋯⋯+1101 and β=99∑r=1r(102−r)(101−r), then the value of α+β is |
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