If A=⎡⎢⎢⎢⎣0−tanθ2tanθ20⎤⎥⎥⎥⎦ and (I2+A)(I2−A)−1=[a−bba] , then 13(a2+b2) is equal to

If A=⎡⎢⎢⎢⎣0−tanθ2tanθ20⎤⎥⎥⎥⎦ and (I2+A)(I2−

1.	If A=⎡⎢⎢⎢⎣0−tanθ2tanθ20⎤⎥⎥⎥⎦ and (I2+A)(I2−A)−1=[a−bba] , then 13(a2+b2) is equal to
Answer» If $A = ⎡ ⎢⎢⎢ ⎣ \begin{matrix} 0 & - tan \frac{θ}{2} tan \frac{θ}{2} & 0 \end{matrix} ⎤ ⎥⎥⎥ ⎦$ and $(I_{2} + A) (I_{2} - A)^{- 1} = [\begin{matrix} a & - b b & a \end{matrix}]$ , then $13 (a^{2} + b^{2})$ is equal to

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If A=⎡⎢⎢⎢⎣0−tanθ2tanθ20⎤⎥⎥⎥⎦ and (I2+A)(I2−A)−1=[a−bba] , then 13(a2+b2) is equal to

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