1.

If 9th term from the end of an A.P is 12th term form the beginning, then the no. of term isWho so ever will give answer fastest I will mark his answer as brainliest.

Answer»

Answer:

Step-by-step explanation:

GIVEN A.P

3,8,13,...…..,253

first term of this A.P a1​=3

second term of this A.P a2​=8

common difference d=a2​−a1​=8−3=5

the NTH term of an A.P is given by

an​=a1​+(n−1)d

an​=3+(n−1)5

an​=3+5n−5

an​=−2+5n…..eq(1)

first calculate number of terms(n) in this A.P

put  an​=253 the last term of A.P in above eq(1)

253=−2+5n

5n=253+2

n=5255​

⟹n=51

hence this A.P CONTAINS 51terms

for calculating 12th term from the END means (51−11)th term from starting of A.P

hence we have to calculate 40th term of this A.P

so put n=40 in eq(1)

a40​=−2+5×40

a40​=−2+200

a40​=198

hence 12th term of from the end of this A.P is 198

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