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If 96500 coulomb of electricity is passed through CuSO4 solution, it will liberate |
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Answer» cathodeCu2+ (aq) + 2e- ---> CU(s)At the anode4OH-(aq) ----> 2H2O (L) + O2(g) + 4e-Faraday’s constant = 96500C/molTo DEPOSIT 1 MOLE of copper, we need 2x96500CSo, 96500C will deposit 0.5 moles of copper = 0.5x63.5 = 31.75gTo LIBERATE one mole of oxygen molecules,we need 4x96500CSo, 96500C will liberate = ¼ = 0.25 moles = 0.25x32 = 8g |
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