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If 8A5146B is divisible by 88, then what is the value of (A + B)? |
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Answer» ANSWER... If it is divisible by 88 then it is divisible by 88 thenit must be divisible by both 8 and 11 it is divisible by 88 thenit must be divisible by both 8 and 11then it is divisible by 88 thenit must be divisible by both 8 and 11then8+5+4+B -(A-1-6) should be divisible by11 it is divisible by 88 thenit must be divisible by both 8 and 11then8+5+4+B -(A-1-6) should be divisible by11= 17+B-A-7 it is divisible by 88 thenit must be divisible by both 8 and 11then8+5+4+B -(A-1-6) should be divisible by11= 17+B-A-7=10 +B -A it is divisible by 88 thenit must be divisible by both 8 and 11then8+5+4+B -(A-1-6) should be divisible by11= 17+B-A-7=10 +B -AAND 46B is divisible by 8 it is divisible by 88 thenit must be divisible by both 8 and 11then8+5+4+B -(A-1-6) should be divisible by11= 17+B-A-7=10 +B -Aand 46B is divisible by 8B is 4 it is divisible by 88 thenit must be divisible by both 8 and 11then8+5+4+B -(A-1-6) should be divisible by11= 17+B-A-7=10 +B -Aand 46B is divisible by 8B is 4then it is divisible by 88 thenit must be divisible by both 8 and 11then8+5+4+B -(A-1-6) should be divisible by11= 17+B-A-7=10 +B -Aand 46B is divisible by 8B is 4then14-A is =11 it is divisible by 88 thenit must be divisible by both 8 and 11then8+5+4+B -(A-1-6) should be divisible by11= 17+B-A-7=10 +B -Aand 46B is divisible by 8B is 4then14-A is =11A is 3 it is divisible by 88 thenit must be divisible by both 8 and 11then8+5+4+B -(A-1-6) should be divisible by11= 17+B-A-7=10 +B -Aand 46B is divisible by 8B is 4then14-A is =11A is 3A×B is 12 Hope this ANSWER helpful to you... |
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