1.

If 6pq3r is exactly divisible by 9 then find the least value of P + Q + r​

Answer»

For a NUMBER to be divisible by 9, it's sum of DIGITS must be divisible by 9.

Sum of digits of 6pq3r = 6+p+q+3+r

= 9+p+q+r (It must be a MULTIPLE of 9. The least value of p+q+r we can take is 0.)

So, 9+0=9. And it is a multiple of 9.

so, the ANSWER is 0.


Discussion

No Comment Found

Related InterviewSolutions