1.

if 62y3 is a multiple of 3, where is y is a single didgit then what should be the minimum and maximum value of y?

Answer»

Step-by-step explanation:

Given If 62y3 is a multiple of 3, where is y is a single digit then what should be the minimum and maximum value of y?

  • We know that a number is divisible by 3, if SUM of digits is divisible by 3
  • 62y3
  • So sum of digits = 6 + 2 + y + 3
  •                            = 11 + y
  • We need to put different values of y and CHECK number is divisible by 3
  • 11 + 0 = 11                           No
  • 11 + 1 = 12                           yes
  • 11 + 2 = 13                          No
  • 11 + 3 = 14                          No
  • 11 + 4 = 15                          yes
  • 11 + 5 = 16                          No
  • 11 + 6 = 17                           No
  • 11 + 7 = 18                         yes
  • 11 + 8 = 19                          No
  • 11 + 9 = 20                         No
  • 11 + 10 = 21                     Yes
  • 11 + 11 = 22                        No
  • Therefore y can be 1,4,7 or 10
  • So minimum value is 1 and maximum is 7


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