If 5x6−9x2+1=(px4+qx3+rx2+sx+t)(ax2+bx+c) , then the value of ap is� – InterviewSolution

1.

If 5x6−9x2+1=(px4+qx3+rx2+sx+t)(ax2+bx+c) , then the value of ap is

Answer»

ong>Answer:

answer is 5

Step-by-step EXPLANATION:

Solution:

(px4+qx3+rx2+sx+t)(ax2+bx+c)

By MULTIPLYING x4 coefficient in px4+qx3+rx2+sx+t and X2 coefficient in ax2+bx+c we get apx6

5x6=apx6

ap=5

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