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If 5th and 6th term of an A.P. are respectively 6 and 5 find the 11th term of the A.P. |
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Answer» Answer: Step-by-step explanation: T5 =a+(n-1) d = 6 =a + 4d =6 ....... (1) T6 = a+(n-1) d = 5 =a+5 d = 5 ..... (2) From 1 and 2 we get =a+5 d = 5 =a + 4d =6 =d = -1 On SUBSTITUTING the VALUE of d in eq 1 =a + 4d =6 =a + 4(-1) =6 =a =6 +4 a = 10 Therefore T11 = =a+(n-1) d = 10 + 10(-1) = 10 -10 = 0 |
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