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If 56 x 32y is divisible by 18, find the least value of y. |
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Answer» It is given that, the number 56 x 32y is divisible by 18. Then, it is also divisible by each factor of 18. Now, the number is divisible by-2, its unit’s digit must be an even number that is 0, 2,4, 6, Therefore, the least value of y is 0. Again, the number is divisible by 3 also, sum of its digits is a multiple of 3. i.e. 5 + 6 + x + 3 + 2 + y is a multiple of 3 => 16 + x + y = 0, 3, 6, 9,… => 16+ x = 18 =>x = 2, which is the least value of x. |
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