If 5 tanA = 4, then find the value of (5 sinA – 3 cosA)/(5 sinA + 2

1.	If 5 tanA = 4, then find the value of (5 sinA – 3 cosA)/(5 sinA + 2 cosA)
Answer» Step-by-step explanation: 5tan = 4 tanA=4/5 p=4 b=5 h= $\sqrt{ {5 }^{2} + {4 }^{2} }$ $\sqrt{25 + 16}$ $\sqrt{41}$ SinA= $4 \div \sqrt{41}$ cosA= $5 \div \sqrt{41}$ 5sinA-3cosA/5sinA+2cosA $5 \times 4 \div \sqrt{41 } - 3 \times 5 \div \sqrt{41} \div 5 \times 4 \div \sqrt{41} + 2 \times 5 \div \sqrt{41}$ $20 \div \sqrt{41} - 15 \div \sqrt{41 } \div 20 \div \sqrt{41} + 10 \div \sqrt{41}$ $5 \div \sqrt{41} \times \sqrt{41} \div 30$ =1/6