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If 5 sec θ – 3 tan θ = 5, then what is the value of 5 tan θ – 3 sec θ? |
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Answer» 5 tan θ -3 sec θ = x …2 On squaring both EQUATIONS and subtracting 2 from 1, (5 sec θ – 3 tan θ)^ 2- (5 tan θ – 3 sec θ)^ 2=25 – X^2 (25 sec 2 θ – 2*5 sec θ*3 tan θ + 9 tan 2 θ) – (25 tan 2 θ – 2*5 sec θ*tan θ+ 9 sec 2 θ)=25-X^2 X^ 2 =25-16=9 X =√9 =±3 |
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