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If 5(-8+6i)/(1+i)=a+ib then a,b​

Answer»

ANSWER:

RATIONALISE denominator

5(-8+6i)×(1-i)÷(1+I)(1-i)=a+ib

5(-8+8i+6i+6)÷(1+1)=a+ib

5÷2(-2+14i)=a+ib

5(-1+7i)=a+ib

a=-5

b=35



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