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If 4th and 9th term of GP are 54 and 13122so 6th term is what

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Answer:

Heya DEAR !

The general formula for the nth term of a geometric PROGRESSION is: 

a(n) = ar^(n-1) 

a : first term 

r : COMMON ratio 

So, the terms of a geometric progression are: 

a, ar, ar², ar^3, ar^4, etc. 

Fourth term: 

ar^3 = 54 

NINTH term: 

ar^8 = 13122 

Dividing the 9th term by the 4th term: 

ar^8 / ar^3 = 13122 / 54 

r^5 = 243 

r = 243^(1/5) 

r = 3 

Now we just need to figure the first term: 

ar^3 = 54 

Plug in r=3: 

a(3^3) = 54 

27a = 54 

a = 54/27 

a = 2 

Answer: 

a(n) = 2*3^(n-1) 

2, 6, 18, 54, 162, 486, etc.

Hope this helps (:

plz mark me as BRAINLIEST!!!!!!!!!!!!1


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