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If `400 Omega` of resistance is made by adding four `100 Omega` resistance of tolerance `5%`, then the tolerance of the combinationsA. 0.2B. 0.05C. 0.1D. 0.15 |
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Answer» Correct Answer - B Resistance of combination, `R_(e)=4R` `(Delta R_(e))/(R_(e))=(Delta R)/(R )=(5xx100)/(100)=5%` |
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