1.

If `400 Omega` of resistance is made by adding four `100 Omega` resistance of tolerance `5%`, then the tolerance of the combinationsA. 0.2B. 0.05C. 0.1D. 0.15

Answer» Correct Answer - B
Resistance of combination, `R_(e)=4R`
`(Delta R_(e))/(R_(e))=(Delta R)/(R )=(5xx100)/(100)=5%`


Discussion

No Comment Found

Related InterviewSolutions