If 4 times the most probable distance of electron of a 1s orbital in a unielectronic atom /ion is given by 0.529 A∘ then the atomic number of the unielectronic species will be. [Given: Wave function of 1s orbital, Ψ=⎷(Z3πa30)e−Zr/a0 where a0 = radius of first Bohr's orbital in H - atom = (52.9 pm) and Z is atomic number of unielectronic species]

If 4 times the most probable distance of electron of a 1s orbital in a

1.	If 4 times the most probable distance of electron of a 1s orbital in a unielectronic atom /ion is given by 0.529 A∘ then the atomic number of the unielectronic species will be. [Given: Wave function of 1s orbital, Ψ=⎷(Z3πa30)e−Zr/a0 where a0 = radius of first Bohr's orbital in H - atom = (52.9 pm) and Z is atomic number of unielectronic species]
Answer» If 4 times the most probable distance of electron of a 1s orbital in a unielectronic atom /ion is given by $0.529 A^{\circ}$ then the atomic number of the unielectronic species will be. [Given: Wave function of 1s orbital, $Ψ = \sqrt{(\frac{Z^{3}}{π a_{0}^{3}})} e^{- Z r / a_{0}}$ where $a_{0}$ = radius of first Bohr's orbital in H - atom = (52.9 pm) and Z is atomic number of unielectronic species]