If 4 tan theta=3 find (4sin theta-3cos theta/4sin theta+3 cos theta) p

1.	If 4 tan theta=3 find (4sin theta-3cos theta/4sin theta+3 cos theta) pls answer it
Answer» rong>Given: $\star \: 4 \tan \theta \: = 3 \\ or \: \\ \star \tan \theta = \frac{3}{4}$ To find: $\star \: \frac{4 \sin \theta - 3 \cos \theta}{4 \sin \theta + 3 \cos \theta} \\$ Solution: $\implies \: \frac{4 \sin \theta - 3 \cos \theta}{4 \sin \theta + 3 \cos \theta} \\$ • Divide both numerator and denominator with [email PROTECTED], we get : $\implies \: \frac{ \frac{ 4 \sin \theta - 3 \cos \theta}{ \cos \theta} }{ \frac{4 \sin \theta + 3 \cos \theta}{ \cos \theta} } \\ \\ \implies \: \frac{4 \tan \theta - 3}{4 \tan \theta + 3}$ Now , put the VALUE of [email protected] $\implies \: \frac{4( \frac{3}{4}) - 3 }{4( \frac{3}{4}) + 3 } \\ \\ \implies \: \frac{3 - 3}{3 + 3} \\ \\ \implies \: \frac{0}{6} = 0$ Hence, the value is 0.

If 4 tan theta=3 find (4sin theta-3cos theta/4sin theta+3 cos theta) pls answer it

Answer»

rong>Given:

$\star \: 4 \tan \theta \: = 3 \\ or \: \\ \star \tan \theta = \frac{3}{4}$

To find:

$\star \: \frac{4 \sin \theta - 3 \cos \theta}{4 \sin \theta + 3 \cos \theta} \\$

Solution:

$\implies \: \frac{4 \sin \theta - 3 \cos \theta}{4 \sin \theta + 3 \cos \theta} \\$

• Divide both numerator and denominator with [email PROTECTED], we get :

$\implies \: \frac{ \frac{ 4 \sin \theta - 3 \cos \theta}{ \cos \theta} }{ \frac{4 \sin \theta + 3 \cos \theta}{ \cos \theta} } \\ \\ \implies \: \frac{4 \tan \theta - 3}{4 \tan \theta + 3}$