1.

If 4 tan theta-3=0 then find : (1)cosec theta (2)cos theta + sec theta

Answer»

theta is written as A,



Given, 4 tanA - 3 = 0


4 tanA = 3


tanA = 3/4





Now,


tanA = 3/4


height / base = 3 / 4






Let height = 3x and base = 4x



By Pythagoras THEOREM,



( 3x )^2 + ( 4x )^2 = hypotenuse^2


25x^2 = hypotenuse^2


5X = hypotenuse





HENCE,


( i ) : cosecA = hypotenuse / height


= 5x / 3x

= 5 / 3



( ii ) :


cosA + SECA


=> base / hypotenuse + hypotenuse / base


=> 4x / 5x + 5x / 4x


=> 4 / 5 + 5 / 4


=> ( 16 + 25 )/20


=> 41/20


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