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If 4 tan θ= 3, evaluate l4sina-eesen19, |
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Answer» Given,4 tan = 3∴ tan = 3/4 As we know,Tan = Perpendicular / baseTan = 3/4Now,Hypotenuse = √3² + 4² = √9+16 = √25 = 5 Using this, we can find:Sin = Perpendicular / Hypotenuse = 3/5Cos = Base / Hypotenuse = 4/5 ATQ,(4sin - cos + 1)/(4sin + cos - 1)= (4 × 3/5 - 4/5 + 1)/(4 × 3/5 + 4/5 - 1) [putting values]= (12 - 4 + 5)/(12 + 4 - 5)= 13/11 hit like if you find it useful |
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