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If 4 cosA +4sinA-5 = O. find the value of sinA |
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Answer» Answer: 4 cos A+4 SinA=5 4cos A=5-4SinA Squaring both sides; we GET 16 cos^2A =25-40 SinA+16 sin^2 A 16-16 sin^2A=25-40SinA+ 16 Sin^2 A 32sin^2 A+40 sinA+9=0 Now using quadratic FORMULA; a=32,b=40,c=9,x=SinA such that SinA=x. Simplify and complete your self. Step-by-step explanation: |
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