1.

If 4 cosA +4sinA-5 = O. find the value of sinA​

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Answer:

4 cos A+4 SinA=5

4cos A=5-4SinA

Squaring both sides; we GET

16 cos^2A =25-40 SinA+16 sin^2 A

16-16 sin^2A=25-40SinA+ 16 Sin^2 A

32sin^2 A+40 sinA+9=0 Now

using quadratic FORMULA;

a=32,b=40,c=9,x=SinA

such that SinA=x. Simplify and complete your self.

Step-by-step explanation:



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