1.

If 4 cos 2 B = 3 , find cosec2 B + sec 2 B - cot2B

Answer»

Answer:

It is GIVEN that 4cotA=3

Thus cotA=43=PB

P=4, B=3

Now, H2=P2+B2

H2=32+42

H2=52

H=5

cosec2A−cot2A=(PH)2−(PB)2 

= (45)2−(43)2

= 1625−169

= 1616

= 1


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