1.

If 3x-2 is the factor of 3x^3+x^2-22x+12 find other factors

Answer»

SOLUTION ☺️

Let p(X)= 3x^3+x^2-22x+12

So,

=)3x-2= 0

=)3x=2

=)x= 2/3

Putting the value of x= 2/3 in p(x)

p( \frac{2}{3}) = 3 (\frac{2}{3} ) {}^{3} + ( \frac{2}{3} ) {}^{2} - 22( \frac{2}{3} ) + 12 \\ = > \frac{8}{9} + \frac{4}{9} - \frac{44}{3} + 12 \\ = > \frac{8 + 4 - 132 + 108}{9} \\ = > \frac{12 - 24}{9} \\ = > - \frac{12}{9} \\ = > - \frac{4}{3} \\ = > other \: factor \: = 3x + 4

HOPE it HELPS ✔️


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