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If 3cos θ = 2 then (2sec2 θ + 2tan2 θ – 7) = ?(a) 0(b) 1(c) 3(4) 4 |
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Answer» If 3cos θ = 2 then (2sec2 θ + 2tan2 θ – 7) = ? (a) 0 (b) 1 (c) 3 (4) 4 |
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