1.

If 31z5 is a multiple of 3. where z is a digit. what might be the value of z ?​

Answer» ONG>Answer:

0

Step-by-step explanation:

Inorder to BECOME a multiple of 3, it should be divisible by 3

Divisibility rule of 3: sum of all digits of that number should be divisible by 3.

31Z5 =9+Z

Here if z=0, then 9+z=9, which is divisible by 3.

So, z can be 0,3,6,9.



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