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If (3+x2008+x2009)2010=a0+a1x+a2x2+…+anxn,then the value ofa0−12a1−12a2+a3−12a4−12a5+a6− ⋯upto n terms is |
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Answer» If (3+x2008+x2009)2010=a0+a1x+a2x2+…+anxn, |
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