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If 3|x| + 5|y| = 8 and 7|x| — 3|y| = 48, then find the value of x + y. A) -5 B) 5C) -4 D) The value does not exist |
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Answer» Correct option is (D) The value does not exist Take |x| = X & |y| = Y Then given system of equations converts into 3X + 5Y = 8 _________(1) & 7X - 3Y = 48 _________(2) Multiply equation (1) by 3 and equation (2) by 5, we get 9X + 15Y = 24 _________(3) & 35X - 15Y = 240 _________(4) By adding equations (3) & (4), we get 44X = 264 \(\Rightarrow\) X = \(\frac{264}{44}\) = 6 \(\therefore\) |x| = 6 \((\because X=|x|)\) Put X = 6 into equation (1), we get \(3\times6+5Y=8\) \(\Rightarrow\) 5Y = 8 - 18 = -10 \(\Rightarrow\) Y = \(\frac{-10}5\) = -2 \(\therefore\) |y| = -2 which is not possible because mode never gives negative value. \((\because Y=|y|)\) Hence, value of y does not exist. Therefore, value of (x + y) does not exist. Correct option is D) The value does not exist |
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