If 3√x+(3√3375) ^3 =17 , then find the cube root of x-1026 is equa

1.	If 3√x+(3√3375) ^3 =17 , then find the cube root of x-1026 is equal to
Answer» SOLUTION :- GIVEN :- $\sf{ \sqrt[3]{x + { \bigg( \sqrt[3]{3375} \bigg)}^{3} } = 17 }$ TO DETERMINE :- $\sf{ \sqrt[3]{x - 1026} }$ EVALUATION :- Here it is given that $\sf{ \sqrt[3]{x + { \bigg( \sqrt[3]{3375} \bigg)}^{3} } = 17 }$ Taking cube in both sides we get $\sf{ {x + { \bigg( \sqrt[3]{3375} \bigg)}^{3} } = {(17)}^{3} }$ $\implies \sf{ {x + { \big( 15 \big)}^{3} } = 4913 }$ $\implies \sf{ x + 3375 = 4913 }$ $\implies \sf{ x = 4913 - 3375 }$ $\implies \sf{x = 1538}$ $\therefore \: \: \: \sf{ \sqrt[3]{x - 1026} }$ $= \sf{ \sqrt[3]{1538 - 1026} }$ $= \sf{ \sqrt[3]{512} }$ $= \sf{ \sqrt[3]{(8 \times 8 \times 8)} }$ $= \sf{8}$ ━━━━━━━━━━━━━━━━ Learn more from Brainly :- 1. 6x2 + x - 15 is DIVIDED by 3x + 5. In each CASE, VERIFY your ANSWER. brainly.in/question/17277773 2. How many 1/2 makes 3 brainly.in/question/28842345