1.

If 3 tan tita =4 find the value of of 4cos tita -sin tita/2cos tita +sin tita​

Answer»

Step-by-step explanation:

3 tan tita =4

so , tan tita =4/3

In triangle ABC

Tan A = BC/AB=4/3

AB= 3

BC = 4

if AB = 3K

BC = 4 K, where K is a positive number

Now,by using PYTHAGORAS theorem

AC square = AB square + BC square

= 3K square + 4K square

AC = 5

cos A = AB/AC

= 3/5

SIN A = BC / AC

= 4/5

4 COS A - SIN A/2 COS A + SIN A

=4 × 3/5 - 4/5

/

2×3/5 - 4/5

= 12 -4/5

/

6-4/5

= 8/5

/

2/5

= 40/10 = 4


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