if 3/4 × 5/3 × 9/5 × a/b = 9/4, then the additive inverse of a/b is

1.	if 3/4 × 5/3 × 9/5 × a/b = 9/4, then the additive inverse of a/b is? a. -1/4 b. -1/9 c. -1 d. -4/9 i found out from a friend that the answer is option c, but i still cant figure out how to do this sum. So pls show the working
Answer» Answer: C) -1 Step-by-step EXPLANATION: Let Multiplicative INVERSE be x 3/4 × 5/3 × 9/5 × a/b = 9/4 => a/b = 9/4 x 4/3 x 3/5 x x5/9 => a/b = 1 so, multipicative inverse of a/b, 1+x=0 =>x= -1 HOPE IT HELPS, PLEASE THANK , FOLLOW AND MARK AS BRAINLIEST.

if 3/4 × 5/3 × 9/5 × a/b = 9/4, then the additive inverse of a/b is? a. -1/4 b. -1/9 c. -1 d. -4/9 i found out from a friend that the answer is option c, but i still cant figure out how to do this sum. So pls show the working

Answer»

Answer:

Step-by-step EXPLANATION:

Let Multiplicative INVERSE be x

3/4 × 5/3 × 9/5 × a/b = 9/4

=> a/b = 9/4 x 4/3 x 3/5 x x5/9

=> a/b = 1

so, multipicative inverse of a/b,

1+x=0

=>x= -1

HOPE IT HELPS,

PLEASE THANK , FOLLOW AND MARK AS BRAINLIEST.