1.

If 2x + 3y =13and xy =4.find the value of 8x^3+27y^3​

Answer»

\huge\mathbf{{\fcolorbox{silver}{silver}{Hey mate, }}}

\huge\mathbf{{\fcolorbox{silver}{silver}{ Answer :}}}

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2x +3y = 13-----(1)

XY =6-----(2)

8x³ +27y³

= (2x)³ +(3y)³

= (2x+3y)³ - 3*2x*3y(2x+3y) [USING (a+b)³ =

a³+b³+3ab(a+b)]

= (13)³- 18 * 6 *13 [ using (1) and (2)]

= 2197 - 1404

=793

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