if 2x^2+3y^2+4z^2-\sqrt{6xy}-2\sqrt{3yz}-2\sqrt{2yz}= 0,then find the value of(2x^2+3y^2+16z^2 +2\sqrt{6xy}.-8\sqrt{3yz}-8\sqrt{2xz}

if 2x^2+3y^2+4z^2-\sqrt{6xy}-2\sqrt{3yz}-2\sqrt{2yz}= 0,then find the

1.	if 2x^2+3y^2+4z^2-\sqrt{6xy}-2\sqrt{3yz}-2\sqrt{2yz}= 0,then find the value of(2x^2+3y^2+16z^2 +2\sqrt{6xy}.-8\sqrt{3yz}-8\sqrt{2xz}
Answer» if 2x^2+3y^2+4z^2-\sqrt{6xy}-2\sqrt{3yz}-2\sqrt{2yz}= 0,then find the value of(2x^2+3y^2+16z^2 +2\sqrt{6xy}.-8\sqrt{3yz}-8\sqrt{2xz}