1.

If 2log(x-y/2)=logx+logy+log3. Then find the value of x/y+y/x=?​

Answer»

2log\frac{x-y}{2} = logx+logy+log3

log[\frac{x-y}{2}]^2 = log[3xy]

[\frac{x-y}{2}]^2 = 3xy

(x-y)^2 = 12xy

x^2+y^2-2xy = 12xy

x^2+y^2 = 14xy

\frac{x^2+y^2}{xy}  = 14

\frac{x}{y} +\frac{y}{x} =14

HOPE IT HELPS!!



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