1.

If ∣∣∣∣2ax1y12bx2y22cx3y3∣∣∣∣=abc2≠0,then the area of the triangle whose vertices are (x1a, y1a), (x2b, y2b), (x3c, y3c) is

Answer»

If
2ax1y12bx2y22cx3y3
=abc20
,

then the area of the triangle whose vertices are (x1a, y1a), (x2b, y2b), (x3c, y3c) is



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