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If 21y5 is a multiple of 9 , where y is a digit. what is the value of y ? |
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Answer» ong>Answer: For the multiple of 9, it MUST should be 2+1+y+5 = (multiple of 9) => 8+y = (multiple of 9) Taking 1 8+1 = 9 which is multiple of 9. And if we take 0 to 9 ACCEPT 1 then ADDITION of 8 and that number will not be multiple of 9. so, y = 1 |
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