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If 21 men and 6 women can do a certain job in 4 days. Also, 6 men and 28 women can do the same job in 3 days. In how many days will 23 men take to do the same job.1. 23/5 days2. 21/5 days3. 26/5 days4. 24/5 days5. 19/5 days |
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Answer» Correct Answer - Option 4 : 24/5 days Given: Time taken by 21 men and 6 women = 4 days. Time taken by 6 men and 28 women = 3 days. Formula Used: Total work = (Number of Persons) × (Time taken) × (Efficiency) Calculation: Let the efficiency of one man and one woman be M and W units per day. Total work done by 21 men and 6 women = (21M + 6W)4 Total work done by 21 men and 6 women = (6M + 28W)3 According to the question, (21M + 6W)4 = (6M + 28W)3 ⇒ 84M + 24W = 18M + 84W ⇒ 66M = 60W ⇒ 11M = 10W ⇒ M/W = 10/11 The efficiency of one man = 10 units The efficiency of one womman = 11 units Total work = (6 × 10 + 28 × 11)3 ⇒ (60 + 308)3 ⇒ 368 × 3 Now the time taken by 23 Men to do the job ⇒ (368 × 3)/(23 × 10) ⇒ 24/5 ∴ 23 men can do the same job in 24/5 days. |
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