1.

If 21 men and 6 women can do a certain job in 4 days. Also, 6 men and 28 women can do the same job in 3 days. In how many days will 23 men take to do the same job.1. 23/5 days2. 21/5 days3. 26/5 days4. 24/5 days5. 19/5 days

Answer» Correct Answer - Option 4 : 24/5 days

Given:

Time taken by 21 men and 6 women = 4 days.

Time taken by 6 men and 28 women = 3 days.

Formula Used:

Total work = (Number of Persons) × (Time taken) × (Efficiency)

Calculation:

Let the efficiency of one man and one woman be M and W units per day.

Total work done by 21 men and 6 women = (21M + 6W)4

Total work done by 21 men and 6 women = (6M + 28W)3 

According to the question,

(21M + 6W)4 = (6M + 28W)3 

⇒ 84M + 24W = 18M + 84W

⇒ 66M = 60W

⇒ 11M = 10W

⇒ M/W = 10/11

The efficiency of one man = 10 units

The efficiency of one womman = 11 units

Total work = (6 × 10 + 28 × 11)3

⇒ (60 + 308)3

⇒ 368 × 3

Now the time taken by 23 Men to do the job 

⇒ (368 × 3)/(23 × 10)

⇒ 24/5

∴ 23 men can do the same job in 24/5 days.



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