If 200 MeV energy is released in the fission of \(^{235}_{92}U\) a si

1.	If 200 MeV energy is released in the fission of \(^{235}_{92}U\) a single nucleus of, how many fissions must occur to produce a power of 1 kW?
Answer» Let the number of fissions per second be n. Then, Energy released per second = n x 200 MeV = n x 200 x 1.6 x 10^-13J Energy required per second = Power x Time = 1kW x 1 s = 1000 J Energy released = Energy required n x 200 x 1.6 x 10^-13 = 1000 n = 3.125 x 10^-13

If 200 MeV energy is released in the fission of \(^{235}_{92}U\) a single nucleus of, how many fissions must occur to produce a power of 1 kW?

Answer»

Let the number of fissions per second be n.

Then, Energy released per second = n x 200 MeV

= n x 200 x 1.6 x 10^-13J

Energy required per second = Power x Time

= 1kW x 1 s = 1000 J

Energy released = Energy required n x 200 x 1.6 x 10^-13 = 1000

n = 3.125 x 10^-13