.if 20 Newton of force is acting on a rectangular surface of length 20

1.	.if 20 Newton of force is acting on a rectangular surface of length 20 cm and 30 cm then find the pressure
Answer» <P>Solution: Given, Force = 20N LENGTH of rectangular surface = 30cm Breadth of rectangular surface = 20cm To find, PRESSURE ___________________________ Firstly finding area of rectangular surface Area of rectangle = length × breadth Ar(rectangle) = 30 × 20 Ar(rectangle) = 600 cm² Converting to m² Ar(rectangle) = 0.6 m² Using the formula P = F/A Where P : pressure = ? F : force = 20N A : area = 600 cm² Substituting the values we have → P = 20/0.6 → P = 20/(6/10) → P = 200/6 → P = 33.33 Pascal (N/m²) Hence , pressure acting of the rectangular surface = 33.33pa

.if 20 Newton of force is acting on a rectangular surface of length 20 cm and 30 cm then find the pressure

Answer»

<P>Solution:

Given,

To find,

___________________________

Firstly finding area of rectangular surface

Area of rectangle = length × breadth

Ar(rectangle) = 30 × 20

Ar(rectangle) = 600 cm²

Converting to m²

Ar(rectangle) = 0.6 m²

Using the formula

P = F/A

Where

Substituting the values we have

→ P = 20/0.6

→ P = 20/(6/10)

→ P = 200/6

→ P = 33.33 Pascal (N/m²)

Hence , pressure acting of the rectangular surface = 33.33pa