1.

If 20.0 ml of 0.500 M KOH is titrated with 0.250 M HNO3, how many millilitres of nitric acid are required to neutralize the base? show formulas and calculations.

Answer»

ong>ANSWER:

molarity and VOLUME of KOH is 0.5M,20ml..

M1=0.5M. V1=20ml

molarity of nitric ACID is 0.25M,volume is ??

M2=0.25M. V2=?

KOH+HNO3--------^ KNO3+H2O

M1V1=M2V2

0.5*20=O.25*V2

V2=40ml



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