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If 20.0 ml of 0.500 M KOH is titrated with 0.250 M HNO3, how many millilitres of nitric acid are required to neutralize the base? show formulas and calculations. |
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Answer» ong>ANSWER: molarity and VOLUME of KOH is 0.5M,20ml.. M1=0.5M. V1=20ml molarity of nitric ACID is 0.25M,volume is ?? M2=0.25M. V2=? KOH+HNO3--------^ KNO3+H2O M1V1=M2V2 0.5*20=O.25*V2 V2=40ml |
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