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If (2^3x-1+10) divided 7=6 find the x value |
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Answer» (2^3x-1+10)/7=6 2^3x-1+10=42 2^3x-1=42-10 2^3x-1=32 we can ALSO write 32 as 2^5 hence: 2^3x-1=2^5 <U>take 2 as common therefore: 3x-1=5 3x=6 therefore x=2 Step-by-step explanation: MARK me as brainliest if u like my answer... |
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