1.

If (2^3x-1+10) divided 7=6 find the x value

Answer»

ANSWER:

(2^3x-1+10)/7=6

2^3x-1+10=42

2^3x-1=42-10

2^3x-1=32

we can ALSO write 32 as 2^5

hence:

2^3x-1=2^5

<U>take 2 as common

therefore:

3x-1=5

3x=6

therefore  x=2

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